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CGP EDU Academic Team
Published on: September 13, 2026
Excess pressure inside a soap bubble is three times that of the other bubble, then the ratio of their volumes will be
Text Solution
Verified by ExpertsThe correct answer is:
C
$\Delta P \propto \frac{1}{r} \Rightarrow \frac{\Delta P_1}{\Delta P_2} = \frac{r_2}{r_1} \Rightarrow \frac{r_2}{r_1} = \frac{3}{1}$ $\therefore \frac{V_1}{V_2} = \left(\frac{r_1}{r_2}\right)^3 = \left(\frac{1}{3}\right)^3 = \frac{1}{27}$
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